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Help!! Are you smarter than a 8th grader?


Petethreeput

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So, I can't change my browser because work is not compatible with ie10. Khan academy is not compatible with my old stuff. I cant find the solution on google, though I can find 8th grade math quizzes.

 

My daughter is confused, I am useless, please help.

 

Find the value of "a" for which the equation is an identity.

 

10x -35 +3ax = 5ax - 7x

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since when did this become mathwrx?

I don't recall the formal definition of what an identity is, but what I think they're asking for as "at which value of a do all the xs cancel each other, leaving -35=0." if that's the case, it becomes an algebra problem with just the as.

10+3a=5a-7
17=2a
a=8.5

I think

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10x -35 +3ax = 5ax - 7x | - 3ax
10x - 35 = 2ax - 7x | +7x
17x - 35 = 2ax | :2x
(17x -35)/ 2x = a

Would be my best guess. Not really an expert though

Edit: Could actually be right, since the value for a will vary accordingly to what x you have, which is the defintion of a function if i remember correctly

 


 

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[quote name='Petethreeput' timestamp='1384308027' post='8140488']
So, I can't change my browser because work is not compatible with ie10. Khan academy is not compatible with my old stuff. I cant find the solution on google, though I can find 8th grade math quizzes.

My daughter is confused, I am useless, please help.

Find the value of "a" for which the equation is an identity.

10x -35 +3ax = 5ax - 7x
[/quote]

Download google chrome for Khan Academy and keep your old version of IE for work.

And I get a = (17x - 35) / (2x)

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Thanks everyone. I had no idea where else to turn. I am not hugely computer literate nor math literate apparently. I remember seeing the calculus question and the answer was automatic and I thought why not try it.

I will look at this problem again, hopefully with new inputs to be successful.

Don't know what my 8th grade math was, but I am pretty sure it wasn't this hard.

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Thanks everyone. I had no idea where else to turn. I am not hugely computer literate nor math literate apparently. I remember seeing the calculus question and the answer was automatic and I thought why not try it.

I will look at this problem again, hopefully with new inputs to be successful.

Don't know what my 8th grade math was, but I am pretty sure it wasn't this hard.

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[quote name='Petethreeput' timestamp='1384374673' post='8144418']
Thanks everyone. I had no idea where else to turn. I am not hugely computer literate nor math literate apparently. I remember seeing the calculus question and the answer was automatic and I thought why not try it.

I will look at this problem again, hopefully with new inputs to be successful.

Don't know what my 8th grade math was, but I am pretty sure it wasn't this hard.
[/quote]

School has gotten harder in my opinion. I am now in the 11th grade in Switzerland and we are doing stuff like combinatorics and proababilty at the moment, but i guess the school system works different here. Always glad to help

 


 

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[quote name='Golfingfanatic' timestamp='1384375273' post='8144446']
[quote name='Petethreeput' timestamp='1384374673' post='8144418']
Thanks everyone. I had no idea where else to turn. I am not hugely computer literate nor math literate apparently. I remember seeing the calculus question and the answer was automatic and I thought why not try it.

I will look at this problem again, hopefully with new inputs to be successful.

Don't know what my 8th grade math was, but I am pretty sure it wasn't this hard.
[/quote]

School has gotten harder in my opinion. I am now in the 11th grade in Switzerland and we are doing stuff like combinatorics and proababilty at the moment, but i guess the school system works different here. Always glad to help
[/quote]

I've never even seen the word combinatorics before.

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I actually like the idea of people posting math problems on here. I say we make a school forum for any questions relating to any subject for help. I mean there are thousands of members on here who would probably have the answer.

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[quote name='Thrillhouse' timestamp='1384406616' post='8146944']
[quote name='Golfingfanatic' timestamp='1384375273' post='8144446']
[quote name='Petethreeput' timestamp='1384374673' post='8144418']
Thanks everyone. I had no idea where else to turn. I am not hugely computer literate nor math literate apparently. I remember seeing the calculus question and the answer was automatic and I thought why not try it.

I will look at this problem again, hopefully with new inputs to be successful.

Don't know what my 8th grade math was, but I am pretty sure it wasn't this hard.
[/quote]

School has gotten harder in my opinion. I am now in the 11th grade in Switzerland and we are doing stuff like combinatorics and proababilty at the moment, but i guess the school system works different here. Always glad to help
[/quote]

I've never even seen the word combinatorics before.
[/quote]

http://www.mathsisfun.com/combinatorics/combinations-permutations.html

 


 

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[quote name='Golfingfanatic' timestamp='1384414941' post='8147174']
[quote name='Thrillhouse' timestamp='1384406616' post='8146944']
[quote name='Golfingfanatic' timestamp='1384375273' post='8144446']
[quote name='Petethreeput' timestamp='1384374673' post='8144418']
Thanks everyone. I had no idea where else to turn. I am not hugely computer literate nor math literate apparently. I remember seeing the calculus question and the answer was automatic and I thought why not try it.

I will look at this problem again, hopefully with new inputs to be successful.

Don't know what my 8th grade math was, but I am pretty sure it wasn't this hard.
[/quote]

School has gotten harder in my opinion. I am now in the 11th grade in Switzerland and we are doing stuff like combinatorics and proababilty at the moment, but i guess the school system works different here. Always glad to help
[/quote]

I've never even seen the word combinatorics before.
[/quote]

http://www.mathsisfun.com/combinatorics/combinations-permutations.html
[/quote]

I'll pass

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[quote name='ralvar' timestamp='1384370023' post='8143984']
[quote name='Petethreeput' timestamp='1384308027' post='8140488']
So, I can't change my browser because work is not compatible with ie10. Khan academy is not compatible with my old stuff. I cant find the solution on google, though I can find 8th grade math quizzes.

My daughter is confused, I am useless, please help.

Find the value of "a" for which the equation is an identity.

10x -35 +3ax = 5ax - 7x
[/quote]

Download google chrome for Khan Academy and keep your old version of IE for work.

And I get a = (17x - 35) / (2x)
[/quote]

I got the same thing. I had to get old school and bust out a paper and pen. Wish I would have seen this post first.

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[quote name='Petethreeput' timestamp='1384308027' post='8140488']
So, I can't change my browser because work is not compatible with ie10. Khan academy is not compatible with my old stuff. I cant find the solution on google, though I can find 8th grade math quizzes.

My daughter is confused, I am useless, please help.

Find the value of "a" for which the equation is an identity.

10x -35 +3ax = 5ax - 7x
[/quote]
10x -35 +3ax = 5ax - 7x
+10x. +10x
-35+3ax=5ax+3x
-5ax. -5ax
-35 -2ax=3x
-2ax=3x+35
In highschool math and this is my best guess . You need a= a value or x= a value to fully solve for the other value

Follow me on Twitter and Instagram @_aaron_wilson

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[quote name='awil' timestamp='1384566751' post='8156074']
[quote name='Petethreeput' timestamp='1384308027' post='8140488']
So, I can't change my browser because work is not compatible with ie10. Khan academy is not compatible with my old stuff. I cant find the solution on google, though I can find 8th grade math quizzes.

My daughter is confused, I am useless, please help.

Find the value of "a" for which the equation is an identity.

10x -35 +3ax = 5ax - 7x
[/quote]
10x -35 +3ax = 5ax - 7x
+10x. +10x
-35+3ax=5ax+3x
-5ax. -5ax
-35 -2ax=3x
-2ax=3x+35
In highschool math and this is my best guess . You need a= a value or x= a value to fully solve for the other value
[/quote]

You messed up with the +10x

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Looking at the equation, divide it into x values and constant values.
This gives 10x + 3ax = 5ax and -35 = -7a.

Taking the 1st equation and subtract 3ax from both sides gives
10x = 2ax. This can be divided by 2x and gives 5 = a.

Using the 2nd equation to check a = 5, we have -35 = -7*5,
and -7*5 = -35, so it checks.

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[quote name='Thrillhouse' timestamp='1384578959' post='8156930']
How come none of the engineers from the calculus thread showed up and did this?
[/quote]

When I posted this, that is exactly what I was thinking. There are some incredibly smart and educated folks on this site, and since I clearly am not one of those, I thought I would try. I also cannot tell you all how much appreciate everyone's help, by those clearly more educated and intelligent than I (regardless of engineering degrees).

Also, "combinatorics" blew my mind. So not only do I not understand 8th grade math, but now I can't hang with 8th grade vocabulary. I am of half a mind to quit my job and go to classes with my daughter so I can consider myself educated.

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I guess the main reason is that they are no longer used to this. I assume "simple" things like that is done automatically by computers, Secondly, if you forget the principle or the definition of something you cannot really come up with a solution.
Combinatorics sucks, trust me^^ Some of these problems can get really tough because sometimes you need to visualize it in a very special way otherwise there is just no formula for that problem.

 


 

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